If D is the mid point of ∆ABC. E is the mid point of CD and F is the mid point of AE then find area of ∆AFD
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Step-by-step explanation:
CD is the median of ∆ABC. Therefore it will divide ∆ABC into two triangles of equal areas.
∴Area(∆ADC)= Area(∆CDB)
In ∆ADC, E is the mid-point of CD. Therefore AE is the median.
∴Area(∆AED) = Area(∆AEC)
In ∆AED, F is the mid-point of AE. Therefore DF is the median.
∴Area(∆AFD)= Area(∆DFE)
8 x Area (AFD)= Area(∆ABC) ,hence proved
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