If each edge of a cube is incyeased by 50%, the percentage increase in the
surface area is
(a) 50%
(b) 75%
(C) 100%
(d) 125%
Answers
Answered by
1
ANS--A
Let the length of one side be 2 cm
Then surface area=6*2*2=24 sq cm
After 50% increase the side becomes 3 cm
Then surface area=6*3*3=54
Percentage increase=(54-24)/24*100=30/24*100=125%
Anonymous:
Thank you
Answered by
2
Answer:
optation ( D ) is correct answer.
understand step by step ....
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Let the length of one side be 2 cm
Then surface area=6*2*2=24 sq cm
After 50% increase the side becomes 3 cm
Then surface area=6*3*3=54
Percentage increase=(54-24)/24*100=30/24*100=125%
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