Question

If each of the three circle of radius 'a' touch the other two. Prove that the area included between them is nearly equal to 4/25 a^2 square units. ​

Answer 1

Answer:

according to the question

radios of each circle= A

let the center of three be A,B and c

Step-by-step explanation:

thus joining the three we get a triangle ABC in which

AB=BC=AC=2a

angle of triangle in each of= 60deg

thus

are of each erc= pil/3 a^2

also area of triangle ABC= root 3/4(29)^2

= root of 3 a^2

thus area left= A^2-pi a^2

= 3.14 - 1.73a^2

=1.41 a^2