Question

\sin ( ^ { 4 } α ) +2 \sin ( ^ { 2 } α ) . \cos ( ^ { 2 } α ) + \cos ( ^ { 4 } α ) =1​

Answer 1

Answer:

Step-by-step explanation:

a² ± 2ab + b² = (a ± b)²

(sin²α)² + 2sin²α cos²α + (cos²α)² = (sin²α + cos²α)² = 1² = 1