If energy stored by capacitor C2 is 40 ), then charge stored by capacitor C, as shown in the figure is (C = 10 uF)
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Ans. 20 micro coulomb
1. equivalent capacitance of parallel combination of two capacitors is 2C
2. since then 2C is in series with another capacitor C of Capacitance 2C, charge is same
3. hence charge on each parallel capacitor C1 and C3 is 40/2 = 20 micro joule
4. V in each parallel capacitor is 2 Volts
5. Charge stored in C1 = 1/2 C V^2= 20 micro coulomb
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