If exterior angle exceeds interior angle by 60° , find the sides of the regular polygon
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hey friend your ans is a regular hexagon i.e 6 sides would do the trick
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SOLUTION:
Let the interior angle be x
thus , exterior angle = x+60
x+x+60=180. ...adjacent angles
x=60
exterior angle =120°
as we know that sum of all the exterior angles of any polygon is 360
so ,360÷120=3
No. of sides =3
SOLUTION:
Let the interior angle be x
thus , exterior angle = x+60
x+x+60=180. ...adjacent angles
x=60
exterior angle =120°
as we know that sum of all the exterior angles of any polygon is 360
so ,360÷120=3
No. of sides =3
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