Question

If f = {(1, 2), (2, -3), (3, -1)} then findi. 2fii. 2 + fiii. f²iv. √f

Answer 1

Given that

f = {(1, 2), (2, -3), (3, -1)}

According to it , we have  

   f(1) = 2   ,     f(2) = - 3   ,   f(3)  = - 1

i. 2f

Solution:  2f(1) = 2(2) = 4  ,     2f(2) = 2(- 3) = -6   ,   2f(3)  = 2(- 1) = -2

ii. 2 + f

Solution:  2 + f(1) = 2 + 2 = 4   ,     2 + f(2) = 2 + ( - 3 ) = 2 - 3 = - 1   ,  

                  2 + f(3)  = 2 + (- 1) = 2 - 1 = 1

iii. f²

Solution:  f^2(1) = 2^2 = 4   ,     f^2(2) = (- 3)^2 = 9   ,   f^2(3)  = (- 1)^2 = 1

iv. √f

Solution:

$\sqrt{f(1)} = \sqrt{2} \\\sqrt{f(2)} = \sqrt{-3} \\\sqrt{f(3)} =\sqrt{-1}$

Answer 2

Step-by-step explanation:

 = {(1, 2), (2, -3), (3, -1)}

According to it , we have  

   f(1) = 2   ,     f(2) = - 3   ,   f(3)  = - 1

i. 2f

Solution:  2f(1) = 2(2) = 4  ,     2f(2) = 2(- 3) = -6   ,   2f(3)  = 2(- 1) = -2

ii. 2 + f

Solution:  2 + f(1) = 2 + 2 = 4   ,     2 + f(2) = 2 + ( - 3 ) = 2 - 3 = - 1   ,  

                  2 + f(3)  = 2 + (- 1) = 2 - 1 = 1

iii. f²

Solution:  f^2(1) = 2^2 = 4   ,     f^2(2) = (- 3)^2 = 9   ,   f^2(3)  = (- 1)^2 = 1

iv. √f

Solution:

\begin{lgathered}\sqrt{f(1)} = \sqrt{2} \\\sqrt{f(2)} = \sqrt{-3} \\\sqrt{f(3)} =\sqrt{-1}\end{lgathered}f(1)=2f(2)=−3f(3)=−1