Math, asked by aasthagarg5003, 1 year ago

If f : R \ {0} → R is defined by f(x) =  x^{3} - \frac{1}{x^{3}} then show that f(x) + f (1/x) = 0.

Answers

Answered by MaheswariS
0

Answer:

See the attachment for detailed solution

Step-by-step explanation:

In the attachment I have answered this problem.

I hope this answer helps you

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Answered by siddhartharao77
1

Answer:

f(x) + f(1/x) = 0

Step-by-step explanation:

Given: f(x) = x³ - (1/x³)

                = (x⁶ - 1)/x³.


f(1/x) = (1/x)³ - (1)/(1/x)³

        = 1/x³ - x³

        = (1 - x⁶)/x³.


LHS:

f(x) + f(1/x)

= (x⁶ - 1)/x³ + (1 - x⁶)/x³

= (x⁶ - 1 + x - x⁶)/x³

= 0.

= RHS


Hope it helps!

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