if f:R ->R is given by f(x) = ex and g: R-> is given by g(y) = sin y, find the composite maooing fog and gof.
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fog = e^sin(x) and gof = sin(e^x).
It is given that f(x) = e^x and g(y) = sin(y)
The composite association is described as comprising one function or mapping onto another function or mapping.
In relations, composite function fog is described as
fog = f(g(x))
since g(x) = sin(x), we can substitute
fog = f(sin(x)) = e^sin(x).
Similarly gof is described as
gof = g(f(x))
since f(x) = e^x, we can substitute
gof = g(e^x)) = sin(e^x)
Hence fog = e^sin(x) and gof = sin(e^x).
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