Question

if f(x)=5x square-4x+5 find f(1) f(-1) f(0)

Answer 1

$f(x) = {5x}^{2} - 4x + 5$

Now,

$f(1) = {5(1)}^{2} - 4(1) + 5 \\ \: \: \: \: \: \: \: \: \: = 5 - 4 + 5 \\ \: \: \: \: \: \: \: \: \: = 10 - 4 = 6$

$f( - 1) = {5( - 1)}^{2} - 4( - 1) + 5 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: = - 5 + 4 + 5 = 4$

$f(0) = {5(0)}^{2} - 4(0) + 5 \\ \: \: \: \: \: \: \: \: \: \: = 0 - 0 + 5 = 5$

Answer 2

Answer:

F(1)*F(-1)*f(0)=

Step-by-step explanation:

Here,

F(1)= 5(1)²-4(1)+5

=5-4+5

=6

f(-1)=5(-1)²-4(-1)+5

=5+4+5

=14

f(0)

= 5(0)²-4(0)+5

=5

NOW,

f(1)*f(-1)*f(0)

=6*15*5

=450