If fig., PQ is a tangent at a point C to a circle with centre O. If AB is a diameter and angle CAB =30degree, find angle PCA.
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answer is 60*
reason:
by tangent-chord theorem,
cab=bcq=30*
acb=90*[angle in a semicircle is 90*]
thus, acb+bcq+pca=180*[angle in a line is 180*]
90+30+pca=180*
pca=180-120=60*
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reason:
by tangent-chord theorem,
cab=bcq=30*
acb=90*[angle in a semicircle is 90*]
thus, acb+bcq+pca=180*[angle in a line is 180*]
90+30+pca=180*
pca=180-120=60*
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