If first term of an ap is a second term is b and last term is 2a then find the sum of the all terms
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a1=a
a2=b
d=a2 - a1
d=b-a
an = 2a
a +( n-1)d = 2a
Subsituting value of a &
a + (n-1)b-a = 2a
(n-1)=a/b-a
n = a/b-a + 1
n=b/b-a
Sn = n/2(a + an)
=b/b-a/2(a + 2a)
=b/2(b-a)×3a
3ab/2(b-a)
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