Question

if h is the HCF of 4052 and 12576 and h=4052×A+ 12576 × B then find the value of {H + A + B}

Answer 1

please mark as brainliest answer

Answer 2

Answer:

The value of H+A+B is 349

Step-by-step explanation:

Given if h is the HCF of 4052 and 12576 and h=4052×A+ 12576 × B then

we have to find the value of h + A + B

$12576= 3\times 4052 +420$

$4052= 9\times 420 +272$

$420= 1\times 272+148$

$272= 1\times 148+124$

$148= 1\times 124+24$

$124 = 5\times 24+4$

$24= 6\times 4+0$  

So HCF = H = 4

$4= 124 - 5\times 24$

 $= 124 - 5 \times (148-124)$

 $= 6 \times 124 - 5 \times 148$

 $= 6\times (272-148) - 5 \times 148$

 $= 6\times 272 - 11\times 148$

 $= 6\times 272 - 11\times (420 - 272)$

 $= 17\times 272 - 11 \times 420$

 $= 17\times (4052 - 420\times 9) - 11 \times 420$

 $= 17 \times 4052 - 164 \times 420$

 $= 17 \times 4052 - 164\times (12576 - 3\times 4052)$

 $= 509\times 4052 -164\times 12576$

Comparing with H = 4052a + 12576b, we get

H=4, A=509 and B= -164

So. H + A + B= 4+509–164=349