if HCF of 408 and 1032is expressible in the form of 1032m -408*5 find M
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By Euclid 's division algorithm,
1032 = 408×2 + 216
408 = 216×1 + 192
216 = 192×1 + 24
192 = 24×8 + 0
Since the remainder becomes 0 here, so HCF of 408 and 1032 is 24
Now,
1032m - 408*5 = HCF of these numbers
=> 1032m - 2040 = 24
=> 1032m = 24+2040
=> m = 2064/1032
=> m = 2
So value of m is 2.
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HCF(408,1032) = 1032m-408*5
HCF(408,1032) = 24
HCF(408,1032) = 24
m = 2
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