Question

If two tangent TP and TQ are drawn from an external point T such that ∠TQP = 60° then find ∠ OPQ.

Answer 1

hey bro
TQ=TP
so , angle TQP=ANGLE TQP
SO ANGLE TPQ=60°
LET ANGLE OPQ=X
ANGLE OPT=90. AND ANGLE TPQ=60
THEREFORE X=90-60
X=30°

Answer 2

ANSWER:
""""""""""""
Given,
angle TQP=60°

Here,

angle OQT and angle OPT are 90°
(angle made by radius and tangent is right angle)
So,
OQP+PQT=90
OQP=90-60
OQP=30°

∆OQP Is isosceles.
so angle OQP = angle OPQ
angle OPQ=30°
**********************
Hope this helps you.

@adharsh26