Question

If HCF of 65 and 117 is of the form (65n – 117), then find n.

Answer 1

I hope this will be helpful

Answer 2

Step-by-step explanation:

117=65×1+52 (by euclid lemma)

65=52×1+13

52=13×4+0

so, 13 is the hcf of these

65n–117=13

65n=13+117

n=130/65=2

gays this is your answer