If I is the current through a wire and 'e' is the charge of electron then the
number of electrons in seconds will be given by –
(A) le/t
(B) e/It
(C) It/e
(D) Ite
Explain the reason for this as well.
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f I is the current through a wire and 'e' is the charge of electron then the
number of electrons in seconds will be given by –
(A) le/t
(B) e/It
(C) It/e
(D) Ite
Explain the reason for this as well.
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