If in A ABC, angle C = 90° and tan A =3/4 , prove that
sin A cos B + cos A sin B = 1.
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Answered by
0
Answer:
b
Step-by-step explanation:
Answered by
9
Answer:
Step-by-step explanation:
In,ΔABC with C=90
We have, tanA=3/4
HENCE,WE GET
AC=4
BC=3
AB=5=√4²+3² Using Pythagorus Theorem!
To prove-sinA*cosB+cosA*sinB
sinA=3/5
cosA=4/5
cosB=3/5
sinB=4/5
=3/5*3/5+4/5*4/5
=9/25+16/25
25/25=1
Hence Proved!
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