Question

if initial velocity of particle is 2m/s and it travels 10m in one second find acceleration​

Answer 1

Answer:

The distance travelled in n seconds is

Sn=un+(1/2)an^2……..(1)

The distance travelled in (n-1) seconds,

S(n-1)=u (n-1)+(1/2)a(n-1)^2=un-u+(1/2)an^2-an+a/2………(2)

The distance travelled in nth second is

Sn-S(n-1)=un+(1/2)an^2-un+u-(1/2)an^2+an-(1/2)a=u+an-a/2=u+a(n-1/2)…..(3)

Now, in the given problem, initial velocity, u=10m/s, acceleration, a=-2m/s^2. Negative sign denotes retardation. n=5.

Substituting these values in equation (3), we have distance travelled in 5th second,

S5-S4=10–2(5–1/2)=10–2(9/2)=10–9=1m

Answer 2

Answer:

1 m

Explanation:

Sn = un + (1/2) an^2……..(1)

The distance travelled in (n-1) seconds,

S(n - 1) = u * (n - 1) + (1/2) * a * (n - 1)^2

= un - u + (1/2) an^2 - an + a/2………(2)

The distance travelled in nth second is

Sn - S(n - 1) = un + (1/2)an^2 - un + u - (1/2)an^2 + an - (1/2)a

= u + an - a/2

= u + a(n - 1/2)…..(3)

Now, according to the question, u = 10m/s, a = - 2m/s^2.

The negative sign denotes retardation n = 5

S5 - S4

= 10 - 2 * (5 - 1/2)

= 10–2(9/2)

= 10 – 9

= 1 m

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