Question

if int x=5,y=10, z=6; , find the value of "z" after solving following statement. z*= y++ + x++ + ++z +y/2;​

Answer 1

Answer:

154

Explanation:

y++ = 10

x++ = 5

++z = 6+1=7

10+5+7 = 22

22*7 = 154

Answer 2

Answer:

I hope it help you

Explanation:

x = x++ + ++y; y = ++x + ++y;  

... + ++y; what are the values of x,y after these are executed ? ... In (2) this is the following operations to be done. i) x ++ ii) y++ iii) y = x + y ... if x = y = 0 initially, both cases will have answer 2, ... x=3 y=4 z=10 #include<stdio.h> int main () { int x=2, y=4; int z=(x++)+x+x+x+x; ... g=c-y ,D=c/y+5 what is the solution of this question