If θ is the angle between two vectors i - 2j + 3k and 3i - 2j + k, find sin θ.
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heya!!!
Cos( x ) = A.B / |A| × |B|
Cos( x ) = 2/14
Cos(x ) = 1 / 7
Cos² (x ) = 1/49
Sin(x) = √ ( 1 - 1 / 49 )
Sin(x) = √48 / 7
Sin(x) = 4√3/7
Have a great future ahead.
Cos( x ) = A.B / |A| × |B|
Cos( x ) = 2/14
Cos(x ) = 1 / 7
Cos² (x ) = 1/49
Sin(x) = √ ( 1 - 1 / 49 )
Sin(x) = √48 / 7
Sin(x) = 4√3/7
Have a great future ahead.
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