Question

if k+1,3k, and 4k+2 be any three consecutive terms of an AP,find value of k

Answer 1

3k-k-1=4k+2-3k
2k-1=k+2
k=3

Answer 2

given terms are in A.P.
then, 2b = a + c
2×3k = ( k+1 ) + ( 4k + 2)
6k = 5k + 3
Thus, k = 3