Question

If k, 2k-1 and 2k+1 are three consecutive terms of an arithmetic progression, the value of k is___

Answer 1

T1 = K , T2 = 2K - 1 and T3 = 2K+1.




First term ( T1 ) = K


Second term ( T2 ) = 2K - 1

And,

Third term ( T3 ) = 2K +1


Common difference ( D ) = T2 - T1


=> 2K - 1 - K


=> ( K - 1 ).


Also,

Common difference ( D ) = T3 - T2



=> 2K - 1 - ( 2K - 1 )


=> 2K - 1 - 2K + 1


=> 2

As we know that , Common difference of an AP is always equal.


So,


T2 - T1 = T3 - T2


K - 1 = 2


K = 2 + 1


K = 3.

Answer 2

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