Question

if k -3, 2k + 1 and 4k + 3 are the three consecutive terms of an ap find the value of k

Answer 1

Answer:

$Value \: of \:k=2$

Step-by-step explanation:

$k-3,\:2k+1\:and\:4k+3\:are\\the\:three\: consecutive\:terms\\of\:A.P$

$we\: know\:that,\\If\:a,b,\:and\:c \:are \: in \:A.P\\\:then\\b-a=c-b$

$Here,\\(2k+1)-(k-3)=(4k+3)-(2k+1)$

$\implies 2k+1-k+3=4k+3-2k-1$

$\implies k+4=2k+2$

$\implies 4-2=2k-k$

$\implies 2=k$

Therefore,

$Value \: of \:k=2$

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Answer 2

Step-by-step explanation:

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