If last term of the sequence -306, -300, -294, -288 .. is zero, then the sum of 10-middle most terms is
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Answered by
3
Answer:
firstly find out no of terms
then 10 middle terms.
and apply sum formula
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Answered by
4
Answer:
Step-by-step explanation:
a=-306
d=-300-(306)=6
an=0
o=-306+(n-1)*6
n-1=306/6=51
n=52
middle most 10 terms are 22 to 31
T22=-306+21*6=126-306=-180
T31=-306+30*6=-306+180=-126
Sum =(t22+T31)/2
=10(-180+126)/2
=-306*5
=-1530
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