Math, asked by yagy143, 1 day ago

If LCM = (32, a) = 64 and HCF (32, a) = 4, then a is equal to​

Answers

Answered by nomu999
21

Answer:

a=8

Step-by-step explanation:

LCM×HCF=product of numbers =32×a

64×4=32×a

256/32=a

a=8

Answered by pulakmath007
18

If LCM = (32, a) = 64 and HCF (32, a) = 4, then a is equal to 8

Given : LCM = (32, a) = 64 and HCF (32, a) = 4

To find : The value of a

Solution :

Step 1 of 2 :

Write down the given data

Here it is given that

LCM = (32, a) = 64 and HCF (32, a) = 4

Step 2 of 2 :

Find the value of a

We know that

HCF × LCM = Product of the numbers

⇒ 4 × 64 = 32 × a

⇒ 32a = 256

⇒ a = 256/32

⇒ a = 8

The value of a = 8

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