if lcm and hcf of two numbers is 32 and 8 respectively and 2nd number is 16 find 1st number
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Answered by
1
hey!! here is ur answer
LCM =32 ; hcf=8; 2nd number=16; 1st number=x
product of two numbers = their ( hcf x LCM)
16x = 32 x 8
16x = 256
x = 256÷16 = 16
hence first number is 16
hope it will help you
LCM =32 ; hcf=8; 2nd number=16; 1st number=x
product of two numbers = their ( hcf x LCM)
16x = 32 x 8
16x = 256
x = 256÷16 = 16
hence first number is 16
hope it will help you
Answered by
2
Answer:
Hey friend,
Here is the answer you are searching for,
Given,
H.C.F = 8
L.C.M = 32
2nd Number = 16
Let 1st number be x,
By using the formula,
H.C.F × L.C.M = Product of both numbers.
=> 32×8 = 16×x
=> x = 32×8/16 = 16
Therefore,
First Number = 16
HOPE IT HELPS YOU.
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