Question

If length of rectangle is incresed by 16%, then how such height should be decresed to constant area?

Answer 1

Let initial length = l
Height = h
Area = lh
Final length = 1.16l
For constant area
lh = 1.16l * H
H = 100/116 h
Percentage decrease
= 1-100/116 * 100%
=16/116 * 100%
= 13.8% (app)
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