If LM || CB and LN || CD , prove that AM/AB = AN/AD .
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Hence proved. As you can see in the image. If you like it I will be pleased
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In ΔABC, given as, DE || AC
Thus, by using Basic Proportionality Theorem, we get,
∴BD/DA = BE/EC ……………………………(i)
In ΔABC, given as, DF || AE
Thus, by using Basic Proportionality Theorem, we get,
∴BD/DA = BF/FE ……………………(ii)
From equation (i) and (ii), we get
BE/EC = BF/FE
Hence, proved.
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