Question

If log(2a-3b)=loga-logb then "a" is?

Answer 1

Answer:

Step-by-step explanation:

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Answer 2

The value of a is $a=\frac{3b^2}{2b-1}$

Step-by-step explanation:

Given : Expression $\log(2a-3b)=\log a-\log b$

To find : The value of 'a'?

Solution :

Step 1 - Write the expression,

$\log(2a-3b)=\log a-\log b$

Step 2 - Apply logarithmic property, $\log a-\log b=\log \frac{a}{b}$

$\log(2a-3b)=\log\frac{a}{b}$

Step 3 - Take anti-log both side,

$2a-3b=\frac{a}{b}$

Step 4 - Solve,

$2ab-3b^2=a$

$2ab-a=3b^2$

$a(2b-1)=3b^2$

$a=\frac{3b^2}{2b-1}$

#Learn more

Loga+logb=log(a+b),then a=

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