Question

A train is travelling at a speed of 90 kmph. Brakes are applied so as to produce a uniform acceleration of -0.5 m/s square. Find how far the train will go before it is brought to rest.

Answer 1

u=90×5/18=25m/s

a=-0.5

v=0

s=?

we know that third equ of motion that is

v^2=u^2+2as

ATQ,

s=v^2-u^2/2a

s=0-×25 ×25 /2×-0.5

s=-625× -0.5

so,

s=312.5 m

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