If log base square root of( 8) x =3 ^1/3 find the value of x?
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Answer:
Simple, use the basic property of logarithms: if a^x = b, then x = log b (base a).
Hence, here,
x = sqrt(8)^10/3 = (2^3/2)^10/3 = 2^(3/2 * 10/3) = 2^5 = 32.
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