Math, asked by akshayk47961, 9 months ago

If log base square root of( 8) x =3 ^1/3 find the value of x?

Answers

Answered by 007692
9

Answer:

Simple, use the basic property of logarithms: if a^x = b, then x = log b (base a).

Hence, here,

x = sqrt(8)^10/3 = (2^3/2)^10/3 = 2^(3/2 * 10/3) = 2^5 = 32.

Answered by panda0413
2

Step-by-step explanation:

there u go

hope it helped

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