If log (m + n) = log 2+ 1 /2 log m + 1 /2 log n, Prove that m=n
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Step-by-step explanation:
(m−1)
m
=n
if logm+logn=log(m+n), find m in terms of n
We can write this as: log(mn)=log(m+n)
∴mn=m+n
Subtracting n from both the sides we get,
mn–n=m
n(m−1)=m
m−1
m
=n
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