Question

If log(x^3-1)-log(x^2+x+1)=0.......................Then what will be the value of x????

Answer 1

hey mate

here is the answer...

Answer:

log (x³-1) - log (x²+x+1)= 0

=>log (x³-1)/(x²+x+1)=0

[quoteint law]

=>log (x-1)(x²+x+1)/(x²+x+1)=0

=>log (x-1)=0

=>log (x-1)= log 1

[taking anti log]

=>x-1=1

=>x=2 (Answer)