Question

If log(x+y)=logx+logy
Then x=

Answer 1

Step-by-step explanation:

log(x-y) =logx-logy

Multiply e^x on both sides. 

e^log(x-y) =e^logx-logy

Cancel log on both sides

x-y=x/y

x=(x+y^2)/y

Hope it helps u