if log4^a+b=2, log2^a-b=2 then find the value of log60^ab
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If loga^b = x
We can conclude that
a^x = b
Similarly in this question
a+b= 4^2 = 16
And a-b = 2^2 = 4
Add both equations
=> 2a= 20 => a= 10
Put in any equation
b= 6
So, ab= 60
We know that loga^a = 1
=> log60^ab = log60^60 = 1
So required answer is 1
We can conclude that
a^x = b
Similarly in this question
a+b= 4^2 = 16
And a-b = 2^2 = 4
Add both equations
=> 2a= 20 => a= 10
Put in any equation
b= 6
So, ab= 60
We know that loga^a = 1
=> log60^ab = log60^60 = 1
So required answer is 1
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