if log7x + log7x2+log7x3= 6 find x
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remember that if log for any number is not given then it is at base 10
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loga+logb+logc=logabc
so here applying it we get
log(7^3*x^6)
=3log7x^2=6
=log7x^2=2
=7x^2=100
or
x=10/(7)^1/2
so here applying it we get
log(7^3*x^6)
=3log7x^2=6
=log7x^2=2
=7x^2=100
or
x=10/(7)^1/2
Pranavbhat16:
thats wrong as log( 7×3×14) ≠ 3log (7*14)
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