if lz-1l<2lz-2l then locus of z=x+iy is
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Answered by
47
Answer:
Hii mate
Step-by-step explanation:
Consider |z+a+bi|=2|z+c+di|. Squaring gives
(x+a)2+(y+b)2=4(x+c)2+4(y+d)2
that is
3(x2+y2)+(8c−2a)x+(8d−2b)y+4c2+4d2−a2−b2=0.
In general this is a circle. Now put in your values of a,…,d
I hope it's helpful ❣❤❣❣✌
Answered by
7
Hy guys
Answer:Step-by-step explanation:|z-4| + |z+4| = 16Let z=x+iyThen|(x+iy)-4|+|(x+iy)+4|=16|(x-4)+iy|+|(x+4)+iy|=16
I hope it will help you ✌✌✌✌✌
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