Math, asked by nithin456, 1 year ago

if lz-1l<2lz-2l then locus of z=x+iy is

Answers

Answered by Anonymous
47

Answer:

Hii mate

Step-by-step explanation:

Consider |z+a+bi|=2|z+c+di|. Squaring gives

(x+a)2+(y+b)2=4(x+c)2+4(y+d)2

that is

3(x2+y2)+(8c−2a)x+(8d−2b)y+4c2+4d2−a2−b2=0.

In general this is a circle. Now put in your values of a,…,d

I hope it's helpful

Answered by Itscharming1
7

Hy guys

Answer:\frac{x^2}{64}+\frac{y^2}{48}=1Step-by-step explanation:|z-4| + |z+4| = 16Let z=x+iyThen|(x+iy)-4|+|(x+iy)+4|=16|(x-4)+iy|+|(x+4)+iy|=16

I hope it will help you

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