if m-n = 16 and m²-n²=400 find mn
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Answered by
5
m-n =16 ----(1)
m^2 - n^2 =400
(m+n)(m-n) =400
(m+n)*16 = 400[from (1)]
m+n = 400/16
m+n = 25---(2)
4mn = (m+n)^2 - (m- n )^2
= (25)^ - (16)^2
4mn = 625 -256
mn = 369/4
m^2 - n^2 =400
(m+n)(m-n) =400
(m+n)*16 = 400[from (1)]
m+n = 400/16
m+n = 25---(2)
4mn = (m+n)^2 - (m- n )^2
= (25)^ - (16)^2
4mn = 625 -256
mn = 369/4
Answered by
5
m-n=16
m^2-n^2=400
we have m^2-n^2=(m+n)(m-n)
(m+n)(m-n)=400
(m+n)(16)=400
m+n=400/16
m+n=25
that is m=25- n
and n=25-m
mn =(25- n)(25-m)
625-25m-25n+mn
m^2-n^2=400
we have m^2-n^2=(m+n)(m-n)
(m+n)(m-n)=400
(m+n)(16)=400
m+n=400/16
m+n=25
that is m=25- n
and n=25-m
mn =(25- n)(25-m)
625-25m-25n+mn
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