If m times the mth term of an AP is equal to the n times nth term then show that the (m + n ) th term of the AP is zero
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Let a be the first term and let d be the common difference. Then...
m times the mth term of is equal to the n times nth term
=> m ( a + (m-1)d ) = n ( a + (n-1 )d )
=> (m-n)a + [ m(m-1) - n(n-1) ] d = 0
=> (m-n)a + [ m² - n² - m + n ] d = 0
=> (m-n)a + [ (m-n)(m+n) - (m-n) ] d = 0
=> a + (m+n-1)d = 0 ... (*)
=> the (m + n)-th term is zero.
Note: In line (*), we have assumed that m≠n. This additional assumption is necessary as the claim is not true if m=n.
sharvarisonone8945:
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He or she is right.
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