If (ma+nb) : b : : (mc+nd) : d, prove that a, b, c, d are in proportion.
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(ma + nb)/b = (mc + nd)/d whence
m(ad -- bc) = n(bd -- bd) giving ad -- bc = 0 as m is not equal to 0.
ad -- bc = 0 OR ad = bc OR a/b = c/d OR a : b :: c : d QED
HOPE IT HELP U ☺☺
m(ad -- bc) = n(bd -- bd) giving ad -- bc = 0 as m is not equal to 0.
ad -- bc = 0 OR ad = bc OR a/b = c/d OR a : b :: c : d QED
HOPE IT HELP U ☺☺
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