Question

If Machine A makes a yo-yo every five minutes and Machine B takes ten minutes to make a yo-yo, how many hours would it take them working together to make 20yo−yos?

Answer 1

Answer:

It will take $1\frac{1}{9}$ hours to make 20 yo-yos

Step-by-step explanation:

Let the hours be x

Machine A makes yo-yo every 5 minutes

In x hours, machine A will make no. of yo-yo = $\frac{x\times 60}{5}=12x$

Machine B makes yo-yo every 10 minutes

Therefore, in x hours, machine B will make no.of yo-yo s

$=\frac{x\times 60}{10}=6x$

According to the question

$12x+6x=20$

$\implies 18x=20$

$\implies x=\frac{20}{18}$

$\implies x=\frac{10}{9}$ hours

or, $x=1\frac{1}{9}$ hours

Therefore it will take $1\frac{1}{9}$ hours to make 20 yo-yos

Hope this helps.

Answer 2

Machine A & Machine B working together will take 7/6 hrs to Make 20 yo-Yos

Step-by-step explanation:

Machine A makes a yo-yo every five minutes

Machine B takes ten minutes to make a yo-yo

in 10 minutes Machine A makes 2 yo-yo & machine B makes 1 yo-yo

=> Every 10 minutes 3 yo-yo is made

=> 6 * 10 = 60 minutes = 3 * 6 = 18 yo-yo would be made

now in next 5 mins machine A will make 1 yo-yo

so in 65 mins 19 yo-yo

and in next 5 mins 1 yo-yo by Machine A & 1 by machine B

Hence 20th & 21st yo-yo will be made together

Hence 20 yo-yos or 21 yo-yos will be ready in 70 Mins

= 1 hr + 10 mins

= 1  + 10/60 hrs

= 1 + 1/6 hrs

= 7/6 hrs

Machine A & Machine B working together will take 7/6 hrs to Make 20 yo-Yos