if momentum of the particle is increased by 100%then the%change in kinetic energy will be-
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Let the momentum of the particle be p ,
p = m × v.
where m is the mass of the particle and v is the velocity of the particle.
Now , Kinetic Energy = 1/2 × ( m v² ).
K.E. = 1/2 × ( m²v² )/m.
K.E. = 1/2 × ( p² )/m.
Now the mass of an object is constant. So the change in momentum is caused by change in velocity .
The momentum is increased by 100 % .
Therefore , the new momentum would be 2p .
And the new K.E. will be
K.E. = 1/2 × ( 4p² ) / m.
i.e., 4 times the old kinetic energy.
∴ So, the percentage increase in kinetic energy will be 300 % .
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