Math, asked by laliadithya1234, 3 months ago

If n(A) = 14, n (B) = 10 and n(AUB) =18
Find
n (ANB)​

Answers

Answered by aditya19121
5

Answer:

  1. answer 6. 24-18 =6. n(AnB) = 6
Answered by abhijattiwari1215
4

Answer:

The vaule of n(A ∩ B) = 6.

Step-by-step explanation:

  • Set is a collection of well defined objects which are distinct from each other.
  • The number of elements in a given finite set is called cardinal number of that finite set and is denoted by n(A).
  • The union of two sets A and B, denoted by (A U B), is the set of all those elements each one of which is either in A or in B or both in A and B.
  • The intersection of two sets A and B denoted by (A ∩ B), is the set of all those elements which are common in both A and B.
  • From set theory:

n(A ∩ B) = n(A) + n(B) - n(A U B)

Given that:

  • n(A) = 14 ; n(B) = 10 and n(A U B) = 18

n(A ∩ B)  = 14 + 10 - 18 \\n(A ∩ B) = 24 - 18 \\ n(A ∩ B) = 6

  • Hence, n(A ∩ B) = 6.
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