Math, asked by sahanasen, 8 months ago

If n(A – B) = 10, n(B- A) = 8, n(A∩ B) = 3, then find
a. n(A∪ B)
b. n(A)
c. n(B)​

Answers

Answered by Anonymous
3

Answer:

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Step-by-step explanation:

only(A) = n(A) - n(A∩ B)

10 =  n(A) - 3

n(A) = 7

only(B) = n(B) - n(A∩ B)

8=  n(B) - 3

n(B) = 5

n(A∪B)=n(A)+n(B)−n(A∩B)

= 7+5-3

= 9

Answered by Aj23445568
0

Answer:

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