If n(A – B) = 10, n(B- A) = 8, n(A∩ B) = 3, then find
a. n(A∪ B)
b. n(A)
c. n(B)
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Step-by-step explanation:
only(A) = n(A) - n(A∩ B)
10 = n(A) - 3
n(A) = 7
only(B) = n(B) - n(A∩ B)
8= n(B) - 3
n(B) = 5
n(A∪B)=n(A)+n(B)−n(A∩B)
= 7+5-3
= 9
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