If n A. M. s introduced between 3 and 17 such that the ratio of last mean to the first mean is 3:1 then the value of n is
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3 + d/17 - d = 1/3
= 9 + 3d = 17 - d
d = 2
= 14/2 = n +1
hence n = 6
= 9 + 3d = 17 - d
d = 2
= 14/2 = n +1
hence n = 6
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