Question

If n is the sum of two consecutive odd integers and less than 100, what is greatest possibility of n?

a. 98

b. 96

c. 94

d. 100

Answer 1

That would be 96 or B because the highest is 47 + 49 and not 49 + 51.

Please mark brainliest or thanks if it helped :D

Answer 2

Answer:  The correct option is (b) 96.

Step-by-step explanation:  Given that n is the um of two consecutive odd integers less than 100.

We are to find the greatest possibility of n.

Since there is a difference of 2 in between two consecutive odd integers, so the two odd integers will be m and ( m + 2).

According to the given condition,

$n=m+(m+2)\\\\\Rightarrow n=2m+2~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)$

Also,

$n<100\\\\\Rightarrow 2m+2<100~~~~~~~~~~~~~~~~~~~~~~[\textup{from equation (i)}]\\\\\Rightarrow 2m<100-2\\\\\Rightarrow 2m<98\\\\\Rightarrow m<\dfrac{98}{2}\\\\\Rightarrow m<49.$

Since m is odd, so the greatest possible value of m is 47.

Therefore, the greatest value of n is given by

$n=2m+2=2\times47+2=94+2=96.$

Thus, the greatest possible value of n is 96.

Option (b) is CORRECT,