Question

if O2 is bubbled thrugh water at 393K how many millimoles of O2 gas would be dissolved in 1L of water? Assume that O2 exerts a pressure of 0.95 bar​

Answer 1

Answer:

According to Henry's Law :

p = KH x C

​KH is the Henry's constant

C is the concentration of oxygen soluble in water  

KH for O2 = 46.82 bar at 393 K

C = 0.95/46.82 = 0.0202 M  

No. of moles = Molarity x Volume = 0.02 x 1 = 0.0202 Moles of Oxygen

Thus no. of millimoles of oxygen soluble in water = 20.2 millimoles  

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