Question

If one angle of a parallelogram is 24° less than
twice the smallest angle then the largest angle
of the parallelogram is
(a) 68°
(b) 102°
(c) 112°
(d) 176°
​

Answer 1

2x-24

and the same as x there must be another angle equal to 2 x - 24

the sum of all quadrilateral 360

so adding all and equating 360

2x - 24 + 2x - 24 + X + X is= 360

6x= 360 + 48

6x=408

x=68

so show the largest angle from here can be dedeuced

2*68-24

which comes to be =112

Answer 2

Step-by-step explanation:

This is the answer of this question