Question

The sum of a number and its reciprocal is -12 what would be the sum of cubes of the two (the number and its reciprocal)?

Answer 1

-12^3 is the answer for your question

Answer 2

The required value is 1764.

Step-by-step explanation:

Let the number be 'x'.

Let its reciprocal be '$\dfrac{1}{x}$'

So, sum of a number and its reciprocal = -12

$x+\dfrac{1}{x}=-12$

Here A = -12

Sum of cubes of the two would be

$x^3+\dfrac{1}{x^3}=(-12)^3-3\times -12\\\\=1728+36\\\\=1764$

Hence, the required value is 1764.

# learn more:

Sum of a number and its reciprocal is 4 then value of sum of cube of the number and reciprocal of the cube is

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